[Icc-mot] ICC12 Advanced V7.03 bug

[Edward Karpicz]

> Thanks for the suggestion Edward, I tried changing to an unsigned 16, but
> the compiler still does a "jsr asr16"
> Bill
>

Then you should check your defines. I tried this, and one case calls asr16, 
another one lsr16. Please attach your code along with all used defines.

#define I16 signed
#define U16 unsigned

short getid(void)
{
short id;

 id    = ((((I16)(CAN0RXIDR0 << 8)) | ((I16)(CAN0RXIDR1)))>> 5);
 id    = ((((U16)(CAN0RXIDR0 << 8)) | ((U16)(CAN0RXIDR1)))>> 5);
}


Edward

>
>
>
>             "Edward Karpicz"
>             <ekarpicz at freemai
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>             04/07/2008 01:03
>             PM                                                    Subject
>                                       Re: [Icc-mot] ICC12 Advanced V7.03
>                                       bug
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>>
>>
>> The code shown needs to do a logical shift right to give me id = 0x0581
>> The compiler uses an arithmatic shift which wraps the sign bit to give me
>> id = 0xFD81
>>
>> CANRIDR0 = 0xB0   CANRIDR1 = 0x20
>>
>>
>> 06B9           ;     id    = ((((I16)(CANRIDR0 << 8)) |
> ((I16)(CANRIDR1)))
>>>> 5);
>
>
>
> What's I16? Is it signed? Replace I16 with U16 and I guess you'll get
> desired result.
>
> Edward
>
>
>
>
>> 06B9 F60161            ldab 0x161
>> 06BC 87                clra
>> 06BD B746              tfr D,Y
>> 06BF C7                clrb
>> 06C0 B60160            ldaa 0x160
>> 06C3 6D80              sty 0,S
>> 06C5 AA80              ora 0,S
>> 06C7 EA81              orb 1,S
>> 06C9 B746              tfr D,Y
>> 06CB CE0005            ldx #5
>> 06CE B764              tfr Y,D
>> 06D0 160000            jsr asr16
>> 06D3 B746              tfr D,Y
>> 06D5 6D83              sty 3,S
>> 06D7                   .dbline 269
>>
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