[Icc-mot] ICC12 Advanced V7.03 bug
willard.a.hall at gm.com
willard.a.hall at gm.com
Mon Apr 7 10:15:10 PDT 2008
Thanks for the suggestion Edward, I tried changing to an unsigned 16, but
the compiler still does a "jsr asr16"
Bill
"Edward Karpicz"
<ekarpicz at freemai
l.lt> To
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04/07/2008 01:03
PM Subject
Re: [Icc-mot] ICC12 Advanced V7.03
bug
Please respond to
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for
ICC08/11/12/16
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>
>
> The code shown needs to do a logical shift right to give me id = 0x0581
> The compiler uses an arithmatic shift which wraps the sign bit to give me
> id = 0xFD81
>
> CANRIDR0 = 0xB0 CANRIDR1 = 0x20
>
>
> 06B9 ; id = ((((I16)(CANRIDR0 << 8)) |
((I16)(CANRIDR1)))
>>> 5);
What's I16? Is it signed? Replace I16 with U16 and I guess you'll get
desired result.
Edward
> 06B9 F60161 ldab 0x161
> 06BC 87 clra
> 06BD B746 tfr D,Y
> 06BF C7 clrb
> 06C0 B60160 ldaa 0x160
> 06C3 6D80 sty 0,S
> 06C5 AA80 ora 0,S
> 06C7 EA81 orb 1,S
> 06C9 B746 tfr D,Y
> 06CB CE0005 ldx #5
> 06CE B764 tfr Y,D
> 06D0 160000 jsr asr16
> 06D3 B746 tfr D,Y
> 06D5 6D83 sty 3,S
> 06D7 .dbline 269
>
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