[Icc-mot] ICC12 Advanced V7.03 bug

[Gene Norris]

Willard,

The below is not much information, please show your function and the
listing (.lis) segment pertinent to this problem.

In general, arithmetic shifts are done on signed values and logical on
unsigned, so you probably have a sign type problem. Data that is not
typed is assumed to be signed...

Gene

willard.a.hall at gm.com wrote:
> 
> The code shown needs to do a logical shift right to give me id = 0x0581
> The compiler uses an arithmatic shift which wraps the sign bit to give me
> id = 0xFD81
> 
> CANRIDR0 = 0xB0   CANRIDR1 = 0x20
> 
> 
>  06B9           ;     id    = ((((I16)(CANRIDR0 << 8)) | ((I16)(CANRIDR1)))
>>> 5);
>  06B9 F60161            ldab 0x161
>  06BC 87                clra
>  06BD B746              tfr D,Y
>  06BF C7                clrb
>  06C0 B60160            ldaa 0x160
>  06C3 6D80              sty 0,S
>  06C5 AA80              ora 0,S
>  06C7 EA81              orb 1,S
>  06C9 B746              tfr D,Y
>  06CB CE0005            ldx #5
>  06CE B764              tfr Y,D
>  06D0 160000            jsr asr16
>  06D3 B746              tfr D,Y
>  06D5 6D83              sty 3,S
>  06D7                   .dbline 269
> 
> _______________________________________________
> Icc-mot mailing list
> Icc-mot at imagecraft.com
> http://dragonsgate.net/mailman/listinfo/icc-mot
> 
> 
>