[Icc-mot] ICC12 Advanced V7.03 bug

[willard.a.hall at gm.com]

The code shown needs to do a logical shift right to give me id = 0x0581
The compiler uses an arithmatic shift which wraps the sign bit to give me
id = 0xFD81

CANRIDR0 = 0xB0   CANRIDR1 = 0x20


 06B9           ;     id    = ((((I16)(CANRIDR0 << 8)) | ((I16)(CANRIDR1)))
>> 5);
 06B9 F60161            ldab 0x161
 06BC 87                clra
 06BD B746              tfr D,Y
 06BF C7                clrb
 06C0 B60160            ldaa 0x160
 06C3 6D80              sty 0,S
 06C5 AA80              ora 0,S
 06C7 EA81              orb 1,S
 06C9 B746              tfr D,Y
 06CB CE0005            ldx #5
 06CE B764              tfr Y,D
 06D0 160000            jsr asr16
 06D3 B746              tfr D,Y
 06D5 6D83              sty 3,S
 06D7                   .dbline 269