[Icc-avr] Re: sprintf limitation?
Paul Mateer
paul.aa9gg at gmail.com
Mon Jul 7 06:51:13 PDT 2008
Hello all....
Thanks for the responses. I found the problem:
a = (VAL[0] - 48) * 10000;
for what ever reason it does not like this. I had to split it up and all is
good now !?
a = (VAL[0] - 48);
a = a * 10000;
----------------------------------------------------------------------------------------------------------------------------------------
On Thu, Jul 3, 2008 at 9:25 AM, Paul Mateer <paul.aa9gg at gmail.com> wrote:
> I'm running into a strange problem. Trying to adjust my var. "max_flow"
> from 0-99999. This sort of works....but only up to 39999!!! Anything 40000
> and above it returns me an "atof error - number to big" . Why? According
> to STDLIB.H max is 2147483520. Ideas???
>
> //-----------------------------------------------------------------------
> double max_flow;
> unsigned long temp;
> char VAL[15];
>
> max_flow = 39999;
>
> temp = (unsigned long)max_flow;
> csprintf(VAL,"%05ld",temp);
>
> dspsingle(0, 'M');
> dspsingle(1, 'X');
> dspsingle(2, '=');
> dspsingle(3, VAL[0]);
> dspsingle(4, VAL[1]);
> dspsingle(5, VAL[2]);
> dspsingle(6, VAL[3]);
> dspsingle(7, VAL[4]);
>
> VAL[0]= (adj_digit((VAL[0]-48), 3)) + 48;
> wait_key();
> VAL[1]= (adj_digit((VAL[1]-48), 4)) + 48;
> wait_key();
> VAL[2]= (adj_digit((VAL[2]-48), 5)) + 48;
> wait_key();
> VAL[3]= (adj_digit((VAL[3]-48), 6)) + 48;
> wait_key();
> VAL[4]= (adj_digit((VAL[4]-48), 7)) + 48;
>
> a = (VAL[0] - 48) * 10000;
> b = (VAL[1] - 48) * 1000;
> c = (VAL[2] - 48) * 100;
> d = (VAL[3] - 48) * 10;
> e = (VAL[4] - 48);
>
> temp = a+b+c+d+e;
> max_flow = temp;
>
> //----------------------------------------------------------------------------------------
>
> --
> Paul Mateer, AA9GG
> Elan Engineering Corp.
> www.elanengr.com
--
Paul Mateer, AA9GG
Elan Engineering Corp.
www.elanengr.com
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